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TABLE 11 (R.F.F. Data).

NUMBEE OF ADULT CHILDREN OF VARIOUS STATURES ]BORN OF 205 D'LD-PARENTS OF VARIOUS STATURES. (All Female Heights have been multiplied by 1-08.)

 

Height of

the mid-

parents in

inches.

Above 72'5...

72.5...

71.5...

70'5...

69.5...

68.5...

67.5...

66.5...

6615 ...

64.5...

Below    

Totals    

Medians    

Below

...

,,.

...

1

1

...

1

1

1

5

...

62.2

...

...

...

.,.

.,.

...

3

3

1

...

63'2

...

...

...

1

1

7

5

3

9

4

2

64.2

...

...

...

16

11

14

5

5

4

4

Heights

 

of

the

adult

 

children.

 

72.2

1

7

9

4

11

4

4

...

1

...

...

73.2

3

2

2

3

4

3

...

...

...

Above.

...

4

2

3

5

...

...

.•

...

14

Total number

of

Medians

or Values

°f ~•

72.2

69.9

69.5

68.9

68.2

67'6

67.9

66.7

6518

65.2

...

...

1

1

4

16

15

2

7

1

1

66.2

...

...

3

1

17

25

36

17

11

5

2

67.2

...

,..

4

3

27

31

38

17

11

5

2

68.2

1

3

12

20

34

28

14

7

...

1

69.2

2

5

18

33

48

38

13

7

2

1

70'2

1

10

14

25

21

19

4

5

...

...

71.2

2

4

7

20

18

11

...

2

...

...

Adult

children.

41

19

43

68

183

219

211

78

66

23

14

928

Mint

parents.

51

6

11

22

41

49

33

20

12

5

1

205

           

-----------

         

7

32

66.3

59

67'8

48

67.9

117

67'7

138

67.9

120

68'3

167

68.5

99

69'0

64

69'0

41

70.0

17

Note.-In calculating the medians, the entries have been taken as referring to the middle of the squares in which they stand. The reason why the headings run 62.2, 63.2, &e., instead of 62'5, 63.5, &c., is that the observations are unequally distributed between 62 and 63, 63 and 64, &c., there being a strong bias in favour of integral inches. After careful consideration, I concluded that the headings, as adopted, best satisfied the conditions. This inequality was not apparent in the case of the mid-parents.

1 I have reprinted this Table without alteration from that published in the Froc. Roy. -Soc., notwithstanding a small blunder since discovered in sorting the entries between the first and second lines. It is obvious that 4 children cannot have 5 MidParents. The first line is not considered at all, on account of the paucity of the numbers it contains. The bottom line, which looks suspicious, is correct.

0 00

H Q

r H

x M

H a


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